LeetCode 232. 用栈实现队列

原题链接:

https://leetcode.com/problems/implement-queue-using-stacks/description/

https://leetcode-cn.com/problems/implement-queue-using-stacks/description/

这道题其实比较简单,题目要求就是用栈实现一个队列。

我们考虑有两个栈,一个输入栈,一个输出栈。

放数据永远放入输入栈,取数据永远从输出栈取。

输出栈为空的时候把把输入栈的数据一次性取出来放到输出栈。

下面是 Java 和 Python 的代码

Java

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class MyQueue {

private Stack<Integer> input = null;
private Stack<Integer> output = null;

/** Initialize your data structure here. */
public MyQueue() {

input = new Stack<>();
output = new Stack<>();

}

/** Push element x to the back of queue. */
public void push(int x) {
input.push(x);
}

/** Removes the element from in front of queue and returns that element. */
public int pop() {
if(output.isEmpty()) {
while(!input.isEmpty()) {
output.push(input.pop());
}
}
return output.pop();
}

/** Get the front element. */
public int peek() {
if(output.isEmpty()) {
while(!input.isEmpty()) {
output.push(input.pop());
}
}
return output.peek();
}

/** Returns whether the queue is empty. */
public boolean empty() {
return input.isEmpty() && output.isEmpty();
}
}

Python

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class MyQueue:

def __init__(self):
"""
Initialize your data structure here.
"""
self.instack = []
self.outstack = []


def push(self, x):
"""
Push element x to the back of queue.
:type x: int
:rtype: void
"""
self.instack.append(x)


def pop(self):
"""
Removes the element from in front of queue and returns that element.
:rtype: int
"""
if not self.outstack:
while self.instack:
self.outstack.append(self.instack.pop())
return self.outstack.pop()


def peek(self):
"""
Get the front element.
:rtype: int
"""
if not self.outstack:
while self.instack:
self.outstack.append(self.instack.pop())
return self.outstack[-1]


def empty(self):
"""
Returns whether the queue is empty.
:rtype: bool
"""
return not self.outstack and not self.instack